Sorted or Not

Accept three integers A, B and C as the input. If A, B and C are in ascending order or in descending order then print “SORTED” as the output else print “NOTSORTED” as the output.

Example Input/Output 1:
Input:
1 4 9

Output:
SORTED

Example Input/Output 2:
Input:
35 23 23

Output:
SORTED

Example Input/Output 3:
Input:
25 37 12

Output:
NOTSORTED

#include <stdio.h>
int main()
{
    int num1, num2, num3;
    scanf("%d%d%d", &num1, &num2, &num3);
    if(num1 <= num2 && num2 <= num3 )
    {
        printf("SORTED");
    }
    else if(num1 >= num2 && num2 >= num3)
    {
        printf("SORTED");
    }
    else
    {
        printf("NOTSORTED");
    }
}

import java.util.*;

public class Hello {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int num1 = sc.nextInt();
        int num2 = sc.nextInt();
        int num3 = sc.nextInt();
        if (num1 <= num2 && num2 <= num3) {
            System.out.println("SORTED");
        } else if (num1 >= num2 && num2 >= num3) {
            System.out.println("SORTED");
        } else {
            System.out.println("NOTSORTED");
        }
    }
}

num1, num2, num3 = map(int, input().split())
if num1 <= num2 and num2 <= num3:
print('SORTED')
elif num1 >= num2 and num2 >= num3:
print('SORTED')
else:
print('NOTSORTED')

#include <iostream>
using namespace std;

int main()
{
    int num1, num2, num3;
    cin >> num1 >> num2 >> num3;
    if(num1 <= num2 && num2 <= num3)
    {
        cout << "SORTED";
    }
    else if(num1 >= num2 && num2 >= num3)
    {
        cout << "SORTED";
    }
    else
    {
        cout << "NOTSORTED";
    }
    return 0;
}