Divide Number by Sum of its Digits

The program must accept an integer N as the input. The task is to compute and print the quotient obtained after dividing N by the sum of its digits.

Boundary Condition(s):
10 <= N <= 10^9

Input Format:
The first line contains the integer N.

Output Format:
A single line contains the quotient value.

Example Input/Output 1:
Input:
48

Output:
6

Explanation:
The sum of digits in 48 is 12 (4+8). 48 divided by 12 gives the quotient 6. Hence the output is 6.

N = int(input().strip())
sum_of_digits = sum(map(int, str(N)))
print(N // sum_of_digits)

#include<stdio.h>

int main() {
    int N, temp, sum = 0;
    scanf("%d", &N);
    temp = N;
    while(temp) {
        sum += temp % 10;
        temp /= 10;
    }
    printf("%d", N / sum);
    return 0;
}

#include <iostream>
using namespace std;

int main() {
    int N, temp, sum = 0;
    cin >> N;
    temp = N;
    while(temp) {
        sum += temp % 10;
        temp /= 10;
    }
    cout << N / sum;
    return 0;
}

import java.util.Scanner;

public class DivideBySum {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int N = sc.nextInt();
        int temp = N, sum = 0;

        while(temp > 0) {
            sum += temp % 10;
            temp /= 10;
        }

        System.out.println(N / sum);
    }
}