Chess Board Pattern

Chess Board Pattern: The program must accept two integers M and N as the input. The program must form a matrix of size (M*N)x(M*N). Then the program must fill the submatrices of size M*M with 0s and 1s alternatively in vertical and horizontal directions as shown in the Example Input/Output section. Finally, the program must print the matrix as the output.

Boundary Condition(s):
2 <= M <= 10
2 <= N <= 25

Input Format:
The first line contains M and N separated by a space.

Output Format:
The first M*N lines containing the matrix.

Example Input/Output 1:
Input:
3 4

Output:
0 0 0 1 1 1 0 0 0 1 1 1
0 0 0 1 1 1 0 0 0 1 1 1
0 0 0 1 1 1 0 0 0 1 1 1
1 1 1 0 0 0 1 1 1 0 0 0
1 1 1 0 0 0 1 1 1 0 0 0
1 1 1 0 0 0 1 1 1 0 0 0
0 0 0 1 1 1 0 0 0 1 1 1
0 0 0 1 1 1 0 0 0 1 1 1
0 0 0 1 1 1 0 0 0 1 1 1
1 1 1 0 0 0 1 1 1 0 0 0
1 1 1 0 0 0 1 1 1 0 0 0
1 1 1 0 0 0 1 1 1 0 0 0

Explanation:
Here M=3 and N=4, so the size of matrix is 12*12 ((3*4)*(3*4)).
In the 12*12 matrix, the submatrices of size 3*3 are filled with 0s and 1s alternatively in vertical and horizontal directions.

Example Input/Output 2:
Input:
2 5

Output:
0 0 1 1 0 0 1 1 0 0
0 0 1 1 0 0 1 1 0 0
1 1 0 0 1 1 0 0 1 1
1 1 0 0 1 1 0 0 1 1
0 0 1 1 0 0 1 1 0 0
0 0 1 1 0 0 1 1 0 0
1 1 0 0 1 1 0 0 1 1
1 1 0 0 1 1 0 0 1 1
0 0 1 1 0 0 1 1 0 0
0 0 1 1 0 0 1 1 0 0

n,m = map(int,input().split())
l = []
k =[]
for i in range(m):
    if i%2 == 0:
        l += [0]*n
        k += [1]*n
    else:
        l += [1]*n
        k += [0]*n
for i in range(m):
    if i%2 == 0:
        for j in range(n):
            print(*l)
    else:
        for j in range(n):
            print(*k)

n,m = map(int,input().split()) l = [] k =[] for i in range(m): if i%2 == 0: l += [0]*n k += [1]*n else: l += [1]*n k += [0]*n for i in range(m): if i%2 == 0: for j in range(n): print(*l) else: for j in range(n): print(*k)

import java.util.*; public class Main { public static void replacewithones(int mat[][],int i,int j,int k) { for(int row=i;row<i+k;row++){ for(int col=j;col<j+k;col++){ mat[row][col]=1; } } } public static void main(String[] args) { int r=2,c=5; int[][] mat=new int[r*c][r*c]; for(int i=0;i<r*c;i+=r){ for(int j=0;j<r*c;j+=r) { if((j/r)%2!=0 && (i/r)%2==0||((i/r)%2!=0 && (j/r)%2==0)) replacewithones(mat,i,j,r); } } for(int i=0;i<r*c;i++){ for(int j=0;j<r*c;j++){ System.out.print(mat[i][j]+" "); } System.out.println(); } } } /* Working correctly but problem is from our side */

#include<stdio.h> #include<stdlib.h> int main() { int a=2, b=5; int r=a*b,c=a*b; int mat[r][c]; int f=0; for(int i=0;i<=r-a;i=i+a){ for(int j=0;j<=c-a;j=j+a){ if(i>0) f=!mat[i-1][j]; for(int i1=i;i1<i+a;i1++){ for(int j1=j;j1<j+a;j1++){ mat[i1][j1]=f; } } if(i==0) f=!f; } } for(int i=0;i<r;i++){ for(int j=0;j<c;j++){ printf("%d ",mat[i][j]); } printf("n"); } }