Except the Nth Position

The program must accept a string value S and an integer N as the input. The program must remove the characters which are present at the positions of multiples of N and then print the modified string as the output.

Boundary Condition(s):
1 <= Length of S <= 100
2 <= N <= Length of S

Input Format:
The first line contains the string S and the integer N.

Output Format:
The first line contains the modified string.

Example Input/Output 1:
Input:
SQUIRRELED 3

Output:
SQIRELD

Explanation:
In the string SQUIRRELED, the characters which are present at the positions of multiples of 3 are U, R and E.
So remove the characters U, R and E in the string SQUIRRELED.
Hence the output is SQIRELD

Example Input/Output 2:
Input:
Banglore 2

Output:
Bnlr

#include <stdio.h>
#include <string.h>

int main() {
    char s[100];
    int a;

    scanf("%s %d", s, &a);

    for(int i = 0; s[i] != ''; i++) {
        if((i + 1) % a != 0) {
            printf("%c", s[i]);
        }
    }

    return 0;
}

s = input().strip()
a = int(input())

for i in range(len(s)):
    if (i + 1) % a != 0:
        print(s[i], end="")

import java.util.Scanner;

public class SkipCharacters {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        String s = scanner.next();
        int a = scanner.nextInt();

        for(int i = 0; i < s.length(); i++) {
            if((i + 1) % a != 0) {
                System.out.print(s.charAt(i));
            }
        }
    }
}

#include <iostream>
#include <string>
using namespace std;

int main() {
    string s;
    int a;

    cin >> s >> a;

    for(int i = 0; i < s.length(); i++) {
        if((i + 1) % a != 0) {
            cout << s[i];
        }
    }

    return 0;
}