Expand alphabets occurrence

A string consisting of short hand form of occurrence of alphabets will be passed as input. The program must expand the code and print the alphabets.

Input Format:
The first line will contain the short hand form of the code of length L.

Boundary Conditions:
2 <= L <= 20

Output Format:
The alphabets occurrence based on the short hand code.


Example Input/Output 1:

Input:
a3b5a2

Output:
aaabbbbbaa

Explanation:
a3 implies a has to occur 3 times and hence a is printed thrice.
b5 implies b has to be occur five times and hence b is printed five times.
a2 again implies a has to occur 2 times and hence a is printed thrice.


Example Input/Output 2:

Input:
z2m6c4

Output:
zzmmmmmmcccc

Example Input/Output 3:

Input:
abc5

Output:
aaaaabbbbbccccc

Explanation:
Here there is no number after a and b. This implies the next immediate number of occurrence is applicable to both a and b.
Hence 5 which occurs after c is applicable to a and b too. So all the three alphabets a,b,c are printed five times.

import java.util.*;
 class Hello {

    public static void main(String[] args) {
     Scanner sc=new Scanner(System.in);
    String str=sc.nextLine();
    char[] ch=str.toCharArray();
    int i,n=ch.length,num,j,l,k;
    String st="";
    for(i=0;i<n;i++)
        {
            if(ch[i]>='a'&&ch[i]<='z')
                st+=ch[i];
            else
                {
                    num=Character.getNumericValue(ch[i]);
                    l=st.length();
                char[] c=st.toCharArray();
                st="";
                for(k=0;k<l;k++)
                {
                    for(j=0;j<num;j++)
                        {
                            st+=c[k];
                        }
                }
                System.out.print(st);
                    st="";
                }
        }
 }
}
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