The function/method concatOrAdd accepts two arguments str1 and str2 representing two string values. The values of both str1 and str2 can be integers or floating point values or words.
The function/method concatOrAdd must return a string based on the following conditions.
– If both str1 and str2 are integers, then the function return their sum as a string.
– If both str1 and str2 are floating point values, then the function return their sum with the precision up to 2 decimal places as a string.
– Otherwise, the function must concatenate both the words and return the concatenated string.
Your task is to implement the function concatOrAdd so that the program runs successfully.
IMPORTANT: Do not write the main() function as it is already defined.
Example Input/Output 1:
Input:
300 450
Output:
750
Explanation:
Both the values are integer values.
So their sum is printed.
Example Input/Output 2:
Input:
15.52 123.676
Output:
139.20
Explanation:
Both the values are floating point values.
So their sum is printed with the precision up to 2 decimal places.
Example Input/Output 3:
Input:
Letus Crack
Output:
LetusCrack
Explanation:
Both the values are string values(words).
So they are concatenated and printed as the output.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char* concatOrAdd(char *str1, char *str2)
{
char* res=(char*)malloc(sizeof(char)*10001);
int f=0;
if(isalpha(str1[0])) {
sprintf(res,"%s",strcat(str1,str2));
return res;
}
for(int i=0;str1[i];++i) {
if(str1[i]=='.') {
f=1;
break;
}
}
if(f)
sprintf(res,"%.2f",atof(str1)+atof(str2));
else
sprintf(res,"%d",atoi(str1)+atoi(str2));
return res;
}
int main()
{
char str1[101], str2[101];
scanf("%s %s", str1, str2);
char *str = concatOrAdd(str1, str2);
if(str == str1 || str == str2)
{
printf("New string is not formedn");
}
if(str[0] == ' ' || str[0] == ' ')
{
printf("String is emptyn");
}
printf("%s", str);
return 0;
}
