JAVA – File Handling – Largest Integer

Java Program to find the largest integer using file Handling

Java File Handling: An array of N integers is read from a file. The file name is stored in the variable fileName. Fill in the missing lines of code to print the largest of N integers.

Boundary Condition(s):
1 <= N <= 1000

Input File Format:
The first line contains N.
The second line contains N integers separated by space(s).

Output Format:
The first line contains an integer.

Example Input/Output 1:
Input:
5
21 56 23 89 64

Output:
89

Example Input/Output 2:
Input:
6
102 456 28 10 23 666

Output:
666

Java File Handling

import java.io.; 
import java.util.;
 public class Hello {
     public static void main(String[] args) {
         Scanner scan = new Scanner(System.in);
         String fileName = scan.next();
         try {
             BufferedReader br=new BufferedReader(new FileReader(fileName));
             String l=br.readLine();
             int count=0;
             while(l!=null){
                 count+=1;
                 if(count==2){
                     String arr[]=l.split(" ");
                     int max=0;
                     for(int i=0;imax){
                             max=current;
                         }
                     }
                     System.out.print(max);
                 }
                 l=br.readLine();
             }
         }
         catch(Exception e){
         }
     }
 }