Division of Largest and Smallest Digits

The program must accept an integer N as the input. The task is to divide the largest digit by the smallest digit in N and print the result.

Boundary Condition(s):
10 <= N <= 10^9

Input Format:
The first line contains the integer N.

Output Format:
A single line contains the result of the division (rounded to 2 decimal places).

Example Input/Output 1:
Input:
4275

Output:
7.00

Explanation:
The largest digit is 7 and the smallest digit is 2. The result of 7 divided by 2 is 3.5. Hence the output is 3.5 rounded to two decimal places.

N = input().strip()
digits = [int(d) for d in N]
print(f'{max(digits)/min(digits):.2f}')

#include<stdio.h>

int main() {
    char N[11];
    scanf("%s", N);
    int max_digit = 0, min_digit = 9;
    for(int i = 0; N[i]; i++) {
        int digit = N[i] - '0';
        if(digit > max_digit) max_digit = digit;
        if(digit < min_digit) min_digit = digit;
    }
    printf("%.2f", (double)max_digit/min_digit);
    return 0;
}

#include <iostream>
#include <iomanip>
using namespace std;

int main() {
    string N;
    cin >> N;
    int max_digit = 0, min_digit = 9;
    for(char ch : N) {
        int digit = ch - '0';
        if(digit > max_digit) max_digit = digit;
        if(digit < min_digit) min_digit = digit;
    }
    cout << fixed << setprecision(2) << (double)max_digit/min_digit;
    return 0;
}

import java.util.Scanner;
import java.text.DecimalFormat;

public class DivMaxMinDigits {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        String N = sc.next();
        int max_digit = 0, min_digit = 9;
        for(char ch : N.toCharArray()) {
            int digit = ch - '0';
            if(digit > max_digit) max_digit = digit;
            if(digit < min_digit) min_digit = digit;
        }
        DecimalFormat df = new DecimalFormat("0.00");
        System.out.println(df.format((double)max_digit/min_digit));
    }
}