A mini bus having S seats can be overbooked during festival times. Out of N bookings made C bookings can be cancelled. Hence the final travelling list has to be prepared for the first S bookings considering the cancellations. Each booking is assigned a PNR. Given the list of PNRs for all the bookings, the program must print the final list of PNRs for the confirmed bookings after cancellation. (The first S bookings remaining after cancellation are considered confirmed)
Input Format:
The first line contains S and N separated by a space.
Next N lines contain the PNRs of the N bookings made.
N+2 th line contains C
Next C lines contain the PNRs of the C bookings cancelled.
Output Format:
S lines contain the PNRs of the confirmed bookings.
Boundary Conditions:
5 <= S <= 30 2 <= N <= 50 N-C > 0
Length of PNR is from 1 to 20
Example Input/Output 1:
Input:
8 10
Q78QJ
BKT6V
32KEW
ETDZI
EH16B
UVZFS
V3ITC
WGGLO
41VJ8
NVIRB
2
UVZFS
BKT6V
Output:
Q78QJ
32KEW
ETDZI
EH16B
V3ITC
WGGLO
41VJ8
NVIRB
import java.util.*;
public class Hello {
public static void main(String[] args) {
Scanner s=new Scanner(System.in);
int m=s.nextInt();
int n=s.nextInt();
Vector<String> v=new Vector<String>(n);
int i;
for(i=0;i<n;i++)
v.add(s.next());
int z=s.nextInt();
for(i=0;i<z;i++)
v.remove(s.next());
for(i=0;i<m&&i<v.size();i++)
System.out.println(v.elementAt(i));
}
}n,m=[int(i) for i in input().split()]
v=[]
for i in range(m):
v.append(input().split())
c=int(input())
for i in range(c):
v.remove(input().split())
for i in range(n):
if i<n and i<len(v):
print(*v[i])#include <iostream>
#include<string.h>
using namespace std;
int main(int argc, char** argv)
{
int s,n,c,i,j;
cin>>s>>n;
char p[n][1000];
int k[n]={0},o=0; // k array act as a status array
for(i=0;i<n;i++)
cin>>p[i];
cin>>c;
char d[100];
for(i=0;i<c;i++){
cin>>d;
for(j=0;j<n;j++)
if(strcmp(d,p[j])==0)
k[j]=1;
}
for(i=0;i<n;i++)
{
if(k[i]==0){
cout<<p[i]<<"n";
o++;}
if(o==s)
break;
}
}
